Hi there!
Don't know if something similary allready been asked but i think something in not right with total mash water calculation.
Let's presume following data is used:
Batch size 19l
Trub loss 1.5l
Boil off 3l
Grain weight 4l
Grain absorption is 3.76l
Let's start
(19L+1.5l)/0.96=21.35l amount of wort after cooling (so far in line with calculation of Beersmith 3 software)
21.35+3=24.35l amount of wort before boil (so far in line with calculation of Beersmith 3 software).
But this is hot, expanded wort!!! So amount of cold wort is 24.35*0.96=23.38l
23.38+3.76=27.14l this is including grain absorption. But Beersmith 3 software calculation is 28.11L which is true in case i mash in with 100C water
PS. I suppose that I know answer to this - mashing in temperature is different every brew and is somethere in 60C-70C, not 20C. This asumption decrease difference in half but anyway this is half a liter in this particular sample which is quite an amount. 8)
Don't know if something similary allready been asked but i think something in not right with total mash water calculation.
Let's presume following data is used:
Batch size 19l
Trub loss 1.5l
Boil off 3l
Grain weight 4l
Grain absorption is 3.76l
Let's start
(19L+1.5l)/0.96=21.35l amount of wort after cooling (so far in line with calculation of Beersmith 3 software)
21.35+3=24.35l amount of wort before boil (so far in line with calculation of Beersmith 3 software).
But this is hot, expanded wort!!! So amount of cold wort is 24.35*0.96=23.38l
23.38+3.76=27.14l this is including grain absorption. But Beersmith 3 software calculation is 28.11L which is true in case i mash in with 100C water
PS. I suppose that I know answer to this - mashing in temperature is different every brew and is somethere in 60C-70C, not 20C. This asumption decrease difference in half but anyway this is half a liter in this particular sample which is quite an amount. 8)